Ultra Rare $20 Gold Piece disguised as Zinclon

[david680]

Found this on the desk today. I believe this is a ultra rare experimental $20 Gold piece disguised as a zinc Lincoln cent. It weighs exactly the same as a zinclon, but I think its actually a ounce of gold compressed into a cent sized piece. Not sure why they did this, but you can look at it and just tell. Any ideas?

 

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[relic nut]

RN I hope you at least hunted the beach area. I'm gonna be up there next week 2 condos down from your property looking for my great grandmother's 12 carat ring she lost in the water while riding her jet ski I hope you'll be home.

Yea man, stop by and we'll pack some soup sandwiches and take my trout dog out for a hunt.

 

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[sutphin]

AS ALL THE POLITICIANS WOULD SAY OLE ABE DID BEST AS PRESIDENT WAS SITTING ON HIS ARSE........

 

[luke_00]

A remarkable piece of history. Congrats! Ive seen some good coins in my days but this is just tops the cake!

 

[Limitool]

Just think, if you took the coin to Jupiter, you would be really rich as Jupiter's gravity is 2.5 times that of Earth's gravity.


Frank

If ya want to lose weight just start here on earth and re-weight a week later on the moon. Works for me. I lost weight almost instantly on my last visit.

 

[G.I.B.]

They're worth about $500 each

Is that in the Greek Euro?

 

[Limitool]

Hmmm, very interesting. I think what you need to do is have a friend drop the coin from a height such that when it hits the ground it will have achieved terminal velocity. That will give off the true sound. Make sure you calculate wind resistance, humidity, and barometric pressure as variables. In case you forgot gravity accelerates at 9.8 meters per second squared.

Mathematically, terminal velocity—without considering buoyancy effects—is given by

V_t= \sqrt{\frac{2mg}{\rho A C_d }}

where

V_t is terminal velocity,
m is the mass of the falling object,
g is the acceleration due to gravity,
C_d is the drag coefficient,
\rho is the density of the fluid through which the object is falling, and
A is the projected area of the object.

In reality, an object approaches its terminal velocity asymptotically.

Buoyancy effects, due to the upward force on the object by the surrounding fluid, can be taken into account using Archimedes' principle: the mass m has to be reduced by the displaced fluid mass \rho\mathcal{V}, with \mathcal{V} the volume of the object. So instead of m use the reduced mass m_r=m-\rho\mathcal{V} in this and subsequent formulas.

On Earth, the terminal velocity of an object changes due to the properties of the fluid, the mass of the object and its projected cross-sectional surface area.

Air density increases with decreasing altitude, ca. 1% per 80 metres (260 ft) (see barometric formula). For objects falling through the atmosphere, for every 160 metres (520 ft) of falling, the terminal velocity decreases 1%. After reaching the local terminal velocity, while continuing the fall, speed decreases to change with the local terminal velocity.
Derivation for terminal velocity

Mathematically, defining down to be positive, the net force acting on an object falling near the surface of Earth is (according to the drag equation):

F_{net} = m a = m g - {1 \over 2} \rho v^2 A C_\mathrm{d}

At equilibrium, the net force is zero (F = 0);

m g - {1 \over 2} \rho v^2 A C_\mathrm{d} = 0

Solving for v yields

v = \sqrt\frac{2mg}{\rho A C_\mathrm{d}}

I am positive this will yield the true nature of the gold and not harm the coin in any way.

For Christ's sake.... I have proven this mathematical formula wrong over and over... just let it go!!!! I and Grandpa Albert did this when I was in the 3rd grade when I proved him wrong. He got it right later.

 

[huntsman53]

Yes, but how will this be effected if this has a rhodium core, rather than solid gold?

Just melt the damn thing down, coat a conical piece of lead with it, seat it into a bullet casing having a primer and filled with gun powder, then shoot one of those ISIS guys about mid-way between his' ears and see what ring you get. You could ask the guy you shot what kind of ring it had but I doubt you will get an answer!


Frank

 

[releventchair]

Reducing it was not as challenging as reducing it to match the diameter of a standard Lincoln Memorial cent.

 

[DirtStalker]

Yea man, stop by and we'll pack some soup sandwiches and take my trout dog out for a hunt.

Well if he's any good I'll cook us up some fishheads and rice

 

[fowledup]

Is pot legal in Florida and Indiana too?

 

[luke_00]

This will sum things up.

 

[DirtStalker]

This will sum things up.

LOL Luke $100 a piece...I've got so many I'll give you a deal $25 a piece

 

[cw0909]

dang, i gave 10 ea.=40 Xs 7 neice & nephew = 280 coin
any ideas on how to get all that gold back

there in this holder


these are the gold ones right

 

[DirtStalker]

dang, i gave 10 ea.=40 Xs 7 neice & nephew = 280 coin
any ideas on how to get all that gold back

there in this holder
View attachment 1184084

these are the gold ones right
View attachment 1184077

Yep steal em back..lol

 

[Rawhide]

Soon to replace the Euro.....

 

[cw0909]

lol, 2 are 18 now about 6'2, 180
me 60+, 5'4 , 150..... not looking good
maybe i can trick em

 

[basque-man]

Found one once. Looks like it was in the ground for maybe a week and fell apart!!!

 

[DirtStalker]

lol, 2 are 18 now about 6'2, 180
me 60+, 5'4 , 150..... not looking good
maybe i can trick em

Threaten to take away phones internet and Xbox. They will throw them at you and gladly.

 

[Carolina Tom]

This is an awesome thread. I am just disappointed that I was not able to find such a coin myself!

 

[DirtStalker]

This is an awesome thread. I am just disappointed that I was not able to find such a coin myself!

Wanna buy some of mine? Only $25 from now til Greece pays off debt