SierraMadre
Jr. Member
Hydrostatic pressure = .052 X weight of fluid in pounds per gallon X height of column of fluid in feet. Water weighs about 8.3 pounds per gallon
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princeipedeleon... I'm wondering If you have a section saaay... Flexihose header ---> Section of Hard PVC Pipe ---> Layflat --- > Section of hard PVC --> Sluice
Use it sort of as a connector in the middle? I wonder if that would work as technically your nozzle and the section of hard pvc are taking up the brunt of the suction force, supplying the layflat as it rolls downhill gaining velocity/keeping suction? BUUUUUT I see a huge problem with layflat in regards to ANY bends/little restrictions along the hose will cause material buildup and be an overall bad day. I like the idea though... *strokes chin*
Here's a site I use for pressure conversions Online Conversion - Pressure Conversion
From their calculations 70' of drop (70 feet of head) will get 30psi so a power jet would be very difficult to use unless you have lots of hose and a tall waterfall above you nearby. A 20' drop will give 8.6 psi of suction at the upper end of the hose, making it doable using the standard 1 hose set up that dumps onto the sluice. However using gravity as a supply for a highbanker is doable, since pressure isn't the issue, only supply gph.
I'm curious about how the layflat, vacuum or pressure thing will work. Good idea for running a highbanker in non-motorized/non-mechanical areas
ok,70 feet of head gives you 30 psi. Now psi stands for "pounds per square inch". A 8 inch diameter hose cross section has c.a. 50 square inches,so we have 50 times 30 pounds of pressure.If we neck down to 1 inch isn,t it 1500 pounds in that square inch in a static (no waterflow)water column? And if we take the cap of and let the water flow,is all that pressure transformed in gph or does the pressure also rise a bit? Has there to be a certain angle when necking down ,like the 11 degree angle in the jetlogs ,so we don,t loose force
Doesn't work that way, the head pressure (psi) in the 1 inch pipe will be the same as the 8 inch pipe, you would just get a reduced flow in GPM. The total height difference between inlet and outlet determines pressure. In your example, the reducer from 8 to 1 inch would feel the load of PSI x square inches minus the area of the 1 inch outlet.