Spot Silver Price Needed to Equal Face for Halves, Quarters & Dimes

Yagershots

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Jun 2, 2011
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Spot Silver Price Needed to Equal Face for Halves, Quarters & Dimes

I thought about this last night and guessed before I went to coinflation.com and found the answer. I was way off. Any guesses / first thoughts? Only talking about the silver content not copper. I only used the simple calculator (http://www.coinflation.com/coins/silver_coin_calculator.html) to come up with my numbers. I'm sure there is a more exact number. John HH
 

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Re: Spot Silver Price Needed to Equal Face for Halves, Quarters & Dimes

Im going to guess somewhere between 1.25 and 1.50
 

Re: Spot Silver Price Needed to Equal Face for Halves, Quarters & Dimes

Since you brought this up, I'll drop one on y'all. In 1931 silver was 30 cents an ounce.

HH

Bentfork
 

Re: Spot Silver Price Needed to Equal Face for Halves, Quarters & Dimes

for 90% fine coins the answer is $1.38 per Troy Oz.

Just set up the equality 0.3617 * (x) = $0.50
Solve for x and get x = $1.38
In case you are wondering 0.3617 is the Troy oz in a 90% half.
It works for all the other 90% fine denominations the same
Dollars: 0.7736 * (x) = $1.00 ; x = $1.38
Quarters: 0.18085 * (x) = $0.25 ; x = $1.38
Dimes: 0.07234 * (x) = $0.10 ; x = $1.38

The only one it doesn't work for is of course the 40% halves because they are only 40% fine and have 0.1475 Troy Oz. per coin
40 Halves: 0.1475 * (x) = $0.50 ; x = $3.39

-Bigheed
 

Re: Spot Silver Price Needed to Equal Face for Halves, Quarters & Dimes

Ok i must just be missing how you guys are doing this problem. I see how they do it on coinflation but i do not see how you guys are doing it can you please explain this a bit more.
 

Re: Spot Silver Price Needed to Equal Face for Halves, Quarters & Dimes

alaskanfever said:
Ok i must just be missing how you guys are doing this problem. I see how they do it on coinflation but i do not see how you guys are doing it can you please explain this a bit more.

as I understand it... 90% $1 face value = .7234 ozt of silver, (its alloyed to be harder/tougher than pure) and the fractionals are fractions of that, so half is 0.3617, quarter would be .180, ect.

so, at $1.38/ozt, the actual silver content of a $1 90% coin, would be just about $1 in silver value.

think of it like lumber, a 2x4 isn't ACTUALLY 2"x4", thats the nominal measurement, what it was when it was cut raw, or whatever. when the silver coin standard was set up, it had a "nominal" value of 1oz = $1, but the actual alloy content of silver is only the .7234.

at least thats how I understand it.
 

Re: Spot Silver Price Needed to Equal Face for Halves, Quarters & Dimes

alaskanfever said:
Ok i must just be missing how you guys are doing this problem. I see how they do it on coinflation but i do not see how you guys are doing it can you please explain this a bit more.

Go to coinflation, click on any particular denomination.. For example, I'll click on 1964 Halves..

Scroll down until you see this:

1. Calculate 90% silver value :

(41.49 × .0321507466 × 12.5 × .90) = $15.0067628598


Here are what those numbers represent

Spot_price x conversion_grams_to_ounces x weight_coin_grams x percent_silver_coin = price

rearrange the formula to get:

Spot_price = price / (conversion_grams_to_ounces x weight_coin_grams x percent_silver_coin)

put the numbers back in the formula (Change the price to $.50), and solve for Spot_price

Spot_price = $.50 / (.0321507466 x 12.5 x .90)

Spot_price = $1.382376745

This will only be the same for Dimes, Quarters, and Halves (90%).. For dollars (morgan and peace), the spot price would be less ($1.29) because they contain more silver than 2 halves, 4 quarters, or 10 dimes.
 

Re: Spot Silver Price Needed to Equal Face for Halves, Quarters & Dimes

I believe a silver dollar contains a little over .77 ozt.
 

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