✅ SOLVED Flat button and musket ball?

[rcumbee64]

I found these two items on a creek bank. Flat button is hard to read. Looks to be "Good Quality" "London".

 

Amazon Forum Fav 👍

Minelab PRO-FIND 35 Waterproof Pinpointer Metal Detector for Experts with Tone ID & Adjustable Sensitivity - Grab it through Amazon!

[Wildcat1750]

Nice flat button find. That could well be a musket ball if it's lead.

 

[TheCannonballGuy]

Brass 1-piece flatbutton with an indented-lettering backmark including the word "London" dates it from about 1810 into the late-1820s/early-1830s. The word "London" of course means it is British-made. Importation of these simple 1-piece brass flatbuttons from Britain into the United States declined drastically when the US button-making industry finally became capable of mass-producing them, about 1830.

The (presumably) lead ball is perfectly-round, so, given that it is the correct size-range, is almost definitely a musket ball or a pistol ball. Need very precise size-measurement to be able to identify its caliber. It is probably from the same time-period as your British-made brass flatbutton, but of course could be a lot earlier.

 

[got2dig]

Good finds, keep digging there will be more nice stuff there.... HH

 

[rcumbee64]

Thanks for the info. I will be digging at this site again soon with hopes of some more great finds!

 

[rcumbee64]

Diameter of the ball is .4895

 

[TheCannonballGuy]

Thank you for providing very-precise measurement of the ball's diameter, which (as I've mentioned) is crucially necessary to get you specific identification of the projectile. Your excavated lead ball's .4895-inch diameter means it was for a Colonial-Era-through-early-1800s .50-caliber musket or rifle... for example, a .50 Hawken Rifle or a .50 Kentucky Rifle.

I should mention, I included the word "excavated" in the above info because being excavated affects your lead ball's diameter. Excavated lead usually (but not absolutely always) has about .005-to-.01-inch of Lead Oxide "patina" on it, which adds to your lead ball's original diameter. On the day it was lost, its diameter was approximately .48-inch... which is correct for a Colonial-to-early-1800s .50-caliber firearm.

 

[rcumbee64]

Thanks!